Order Seven Cyclic Groupdoku


I will start by assuring anyone fearful of the word 'group' that this is a totally accessible puzzle for all.  By saying we are working over the cyclic group of order seven, all we mean is that we are using only the numbers 0,1,2,3,4,5 and 6 and adding.  Whatever the result is, we subtract 7's until we get one of the numbers we are using.  For example 5+4=9 in the integers, but since 9 isn't one of our numbers, we subtract 7 to get to 2, which is one of our numbers so we stop.  Similarly, the sum of 3, 4, and 6 would be 13 which turns into 6, and the sum of 6, 5, and 6 is 17 which turns into 3 after subtracting seven twice.  This is much like the calculations you do when you want to see what time it is four hours after 10am, where you might take 10+4=14 but then subtract 12 in order to get to 2pm.

Now that that is done, this puzzle is much like doing normal Calcudoku or KenKen, except with this new addition.  This means that each of the numbers 0,1,2,3,4,5 and 6 must appear exactly once in each row and column, and that the clues in each cage represent the sum of the numbers in the cells of that cage.

Though I've posted cyclic groupdoku of certain orders before, I'll mention that this puzzle is the first one I've constructed over the cyclic group of order seven.  Seven is a nice number for getting a puzzle that's not entirely trivial, but still not too hard for newcomers first jumping in.

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Solution

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